(2y^2-3y-5)=0

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Solution for (2y^2-3y-5)=0 equation:


Simplifying
(2y2 + -3y + -5) = 0

Reorder the terms:
(-5 + -3y + 2y2) = 0

Remove parenthesis around (-5 + -3y + 2y2)
-5 + -3y + 2y2 = 0

Solving
-5 + -3y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-1 + -1y)(5 + -2y) = 0

Subproblem 1

Set the factor '(-1 + -1y)' equal to zero and attempt to solve: Simplifying -1 + -1y = 0 Solving -1 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1y = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1y = 0 + 1 -1y = 0 + 1 Combine like terms: 0 + 1 = 1 -1y = 1 Divide each side by '-1'. y = -1 Simplifying y = -1

Subproblem 2

Set the factor '(5 + -2y)' equal to zero and attempt to solve: Simplifying 5 + -2y = 0 Solving 5 + -2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2y = 0 + -5 -2y = 0 + -5 Combine like terms: 0 + -5 = -5 -2y = -5 Divide each side by '-2'. y = 2.5 Simplifying y = 2.5

Solution

y = {-1, 2.5}

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